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JEE · NEET Physics

Class 11 · Chapter 12

Thermodynamics

Overview, notes, short notes, formula sheet, daily practice problems, previous year questions, and videos for this chapter — all in one place.

Thermodynamics Formula Sheet

12 formulas across 3 topics in Thermodynamics.

1 min read

Updated 2026-07-04 · v1.0.1

First Law & Work Done by a Gas

Energy bookkeeping: heat in = internal energy change + work out. Signs are everything in this chapter.

Q = ΔU + W

First law of thermodynamics

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
Qheat SUPPLIED to the gas (positive in)J[ML²T⁻²]
ΔUchange in internal energyJ[ML²T⁻²]
Wwork done BY the gas (positive out)J[ML²T⁻²]

Valid when

  • Sign convention above is the NCERT/exam standard — chemistry uses W done ON the gas

Common mistakes

  • ΔU depends ONLY on temperature change for an ideal gas — same ΔT means same ΔU regardless of the process

W = ∫ P dV (area under the P–V curve)

Work done by a gas

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
Pgas pressureN/m²[ML⁻¹T⁻²]
dVinfinitesimal volume change[L³]

Valid when

  • Expansion → W positive; compression → W negative
  • For a CYCLE, net work = area enclosed by the loop (positive if clockwise on a P–V diagram)

Common mistakes

  • Work is PATH-dependent — two processes between the same states generally do different work
  • Anticlockwise P–V loops have NEGATIVE net work — the cycle is a refrigerator, not an engine

ΔU = n Cᵥ ΔT (any process, ideal gas)

Internal energy change of an ideal gas

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
nnumber of molesmol[N]
Cᵥmolar heat capacity at constant volumeJ/(mol·K)[ML²T⁻²Θ⁻¹N⁻¹]

Valid when

  • Holds for EVERY process of an ideal gas, not only isochoric — U is a state function of T alone

Cₚ − Cᵥ = R; γ = Cₚ/Cᵥ

Mayer's relation & adiabatic exponent

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First law applied to an isobaric process of an ideal gas

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
Cₚ, Cᵥmolar heat capacities at constant pressure and volumemonatomic: Cᵥ = 3R/2, γ = 5/3; diatomic: Cᵥ = 5R/2, γ = 7/5J/(mol·K)[ML²T⁻²Θ⁻¹N⁻¹]
Runiversal gas constantR = 8.314 J/(mol·K)J/(mol·K)[ML²T⁻²Θ⁻¹N⁻¹]

Valid when

  • Cₚ > Cᵥ always: at constant pressure some heat leaves as expansion work

Worth remembering

  • Free expansion into vacuum: W = 0, Q = 0, so ΔU = 0 and temperature is unchanged (ideal gas) — no formula, pure first law

Thermodynamic Processes

Each named process kills one variable: isothermal fixes T, isochoric fixes V, isobaric fixes P, adiabatic blocks heat. Know W and Q for each.

W = nRT ln(V₂/V₁) (isothermal)

Work in an isothermal process

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W = ∫P dV with P = nRT/V

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
V₁, V₂initial and final volumes[L³]
Tconstant temperatureK[Θ]

Valid when

  • ΔU = 0, so Q = W — all heat becomes work
  • Slow (quasi-static) process in a conducting vessel

PV^γ = constant; TV^(γ−1) = constant

Adiabatic process relations

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First law with Q = 0 combined with the ideal gas law

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
γadiabatic exponent Cₚ/Cᵥdimensionless[M⁰L⁰T⁰]

Valid when

  • No heat exchange (fast process or insulated walls)
  • Adiabatic curve is STEEPER than the isothermal through the same point (slope ratio = γ)

Common mistakes

  • Adiabatic expansion COOLS the gas — work is paid from internal energy

W = (P₁V₁ − P₂V₂)/(γ − 1) = nR(T₁ − T₂)/(γ − 1)

Work in an adiabatic process

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W = −ΔU = −nCᵥΔT with Cᵥ = R/(γ−1)

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
T₁, T₂initial and final temperaturesK[Θ]

Valid when

  • Positive for expansion (T₂ < T₁)

C = Cᵥ + R/(1 − x) for PV^x = constant

Molar heat capacity of a polytropic process

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
xpolytropic indexx = 0 isobaric, 1 isothermal, γ adiabatic, ∞ isochoricdimensionless[M⁰L⁰T⁰]
Cmolar heat capacity of the processJ/(mol·K)[ML²T⁻²Θ⁻¹N⁻¹]

Valid when

  • C can be NEGATIVE for 1 < x < γ — the gas cools while absorbing heat

Worth remembering

  • Process-spotting on a P–V diagram: hyperbola = isothermal, steeper falling curve = adiabatic, vertical = isochoric, horizontal = isobaric

NEET asks W/Q/ΔU signs per process; JEE Advanced chains processes into cycles and asks for net quantities — tabulate each leg first.

Heat Engines, Refrigerators & Second Law

No engine beats Carnot between the same two reservoirs. Efficiency and COP are just ratios of the same three energy flows.

η = W/Q₁ = 1 − Q₂/Q₁

Efficiency of a heat engine

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
Q₁heat absorbed from the hot reservoirJ[ML²T⁻²]
Q₂heat rejected to the cold reservoirJ[ML²T⁻²]
Wnet work output (= Q₁ − Q₂)J[ML²T⁻²]

η(cycle) = W(net)/Q(in) = (area enclosed on P–V) / (heat absorbed in the positive-Q legs)

Efficiency of a general P–V cycle

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Over a full cycle ΔU = 0, so W(net) = Q(net) = Q(in) − Q(out)

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
W(net)net work per cycle (enclosed area, clockwise positive)J[ML²T⁻²]
Q(in)heat ABSORBED (sum over legs where Q > 0 only)J[ML²T⁻²]

Valid when

  • Compute Q leg-by-leg first (nCᵥΔT, nCₚΔT, or nRT ln for isothermal), THEN sum only the positive ones for Q(in)

Common mistakes

  • Dividing by total heat exchanged |Q(in)| + |Q(out)| instead of Q(in) alone — the definition uses only absorbed heat

η(Carnot) = 1 − T₂/T₁

Carnot efficiency

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For the reversible Carnot cycle, Q₂/Q₁ = T₂/T₁

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
T₁, T₂hot and cold reservoir temperaturesK[Θ]

Valid when

  • Temperatures in KELVIN, always
  • This is the maximum possible efficiency between T₁ and T₂ — no real engine reaches it
  • η = 1 only if T₂ = 0 K, which is unattainable

Common mistakes

  • Plugging Celsius values is the single most common thermodynamics error in NEET

COP = Q₂/W = T₂/(T₁ − T₂) (Carnot refrigerator)

Coefficient of performance of a refrigerator

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
COPcoefficient of performancecan exceed 1 — and usually doesdimensionless[M⁰L⁰T⁰]
Q₂heat extracted from the cold spaceJ[ML²T⁻²]

Valid when

  • Relation to the same-reservoir engine: COP = (1 − η)/η

Common mistakes

  • A refrigerator does not 'create cold' — it pumps Q₂ + W into the room; running one with the door open WARMS the room

Worth remembering

  • Second law in one line: heat cannot flow spontaneously from cold to hot, and no cyclic engine can convert heat entirely into work

NEET recycles Carnot-with-changed-reservoirs numericals; JEE Main likes 'efficiency becomes double when T₂ is lowered by x' algebra.

Stuck on a concept in Thermodynamics?

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