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JEE · NEET Physics

Class 11 · Chapter 16

Circular Motion

Overview, notes, short notes, formula sheet, daily practice problems, previous year questions, and videos for this chapter — all in one place.

Circular Motion Formula Sheet

16 formulas across 3 topics in Circular Motion.

1 min read

Updated 2026-07-08 · v1.0.0

Angular Kinematics

Angular kinematics mirrors linear kinematics exactly — every SUVAT-style equation has a direct rotational twin, with θ, ω, α replacing x, v, a.

ω = dθ/dt (instantaneous); ω(avg) = Δθ/Δt

Angular velocity

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
ωangular velocityrad/s[T⁻¹]
θangular positionrad[M⁰L⁰T⁰]

Valid when

  • A vector quantity; direction along the rotation axis via the right-hand rule

α = dω/dt

Angular acceleration

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
αangular accelerationrad/s²[T⁻²]

Valid when

  • Zero for uniform circular motion (ω constant) — non-zero only when speed along the circle changes

ω = ω₀ + αt ; θ = ω₀t + ½αt² ; ω² = ω₀² + 2αθ

Equations of motion for constant angular acceleration

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Direct rotational analogues of the linear SUVAT equations, ω↔v, θ↔x, α↔a

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
ω₀initial angular velocityrad/s[T⁻¹]

Valid when

  • Valid only for CONSTANT angular acceleration — same restriction as the linear SUVAT set

v = rω ; a(tangential) = rα

Relation between linear and angular quantities

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Arc length s = rθ, differentiated once for v = rω and again for aₜ = rα

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
rradius of the circular pathm[L]
vlinear (tangential) speedm/s[LT⁻¹]

Valid when

  • r is measured from the axis of rotation, not from some arbitrary point

Common mistakes

  • For points at different radii on the same rigid rotating body, ω is the SAME for all of them, but v = rω differs — a very common source of error in rigid-body problems

T = 2π/ω = 1/f ; ω = 2πf

Time period and frequency of circular motion

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Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
Ttime for one complete revolutions[T]
ffrequency (revolutions per second)Hz[T⁻¹]

Centripetal Acceleration & Force

Moving in a circle at constant speed still means accelerating — the velocity's DIRECTION is constantly changing, and that requires a net inward force at every instant.

a(c) = v²/r = ω²r

Centripetal (radial) acceleration

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Rate of change of the velocity vector's DIRECTION (not magnitude) for motion along a circle

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
a(c)centripetal acceleration, directed toward the centrem/s²[LT⁻²]

Valid when

  • Present even in UNIFORM circular motion (constant speed) — direction alone changing is enough to require this acceleration

Common mistakes

  • Centripetal acceleration is NOT a separate force by itself — it's the acceleration that some real force (tension, gravity, friction, normal force) must supply

a(net) = √(a(c)² + a(t)²)

Net acceleration in non-uniform circular motion

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Radial (centripetal) and tangential acceleration components are always perpendicular, so they combine via Pythagoras

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
a(t)tangential acceleration, from the changing SPEEDm/s²[LT⁻²]

Valid when

  • a(t) = 0 for uniform circular motion, leaving only a(c) — total acceleration then points purely radially inward

F(c) = mv²/r = mω²r

Centripetal force

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Newton's second law applied along the radial direction: F = ma(c)

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
mmass of the object moving in the circlekg[M]

Valid when

  • Not a NEW type of force — it's whichever real force (or component of it) happens to point toward the centre

Common mistakes

  • Never add 'centripetal force' as an extra arrow on a free-body diagram alongside gravity/tension/normal — it IS the net inward component of those real forces

F(cf) = −mω²r (pseudo force, rotating frame only)

Centrifugal force (pseudo force)

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Valid when

  • Only appears when analysing motion from within the ROTATING (non-inertial) frame — has no place in an inertial-frame free-body diagram

Common mistakes

  • Mixing centrifugal force into an inertial-frame analysis alongside real forces is a direct contradiction — pick ONE frame and stay consistent

Worth remembering

  • Every circular-motion problem starts the same way: identify which real force(s) — or components of them — supply the required centripetal force, then apply F(net, radial) = mv²/r

Banking of Roads, Conical Pendulum & Vertical Circle

These three classic setups are the same centripetal-force idea applied to increasingly clever geometries — each one is a guaranteed numerical question in JEE/NEET.

v(max) = √(μrg)

Maximum speed on a flat (unbanked) circular road

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Friction alone supplies the centripetal force: μmg = mv²/r

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
μcoefficient of friction between tyres and roaddimensionless[M⁰L⁰T⁰]
gacceleration due to gravitym/s²[LT⁻²]

Valid when

  • Beyond this speed, the car skids outward — friction alone cannot provide enough centripetal force

tanθ = v²/rg

Banking angle for a frictionless banked road

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Only normal force provides centripetal force: N sinθ = mv²/r, with N cosθ = mg vertically

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
θangle of banking of the roadrad[M⁰L⁰T⁰]

Valid when

  • This is THE ONE ideal safe speed for a given banking angle when friction is completely absent

v(max) = √[rg(tanθ + μ) / (1 − μtanθ)]

Maximum safe speed on a banked road WITH friction

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Both normal force and friction (acting down the incline, at the verge of outward skidding) contribute to the centripetal force

Valid when

  • Minimum safe speed (verge of sliding DOWN and inward) replaces + with − in both places: v(min) = √[rg(tanθ − μ)/(1+μtanθ)]

Common mistakes

  • This formula reduces correctly to both simpler cases: set μ = 0 to recover tanθ = v²/rg, or θ = 0 to recover the unbanked-road result

tanθ = v²/rg ; T(period) = 2π√(l cosθ / g)

Conical pendulum — angle and time period

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Tension's horizontal component supplies centripetal force; vertical component balances gravity — identical structure to frictionless banking

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
llength of the stringm[L]
θangle the string makes with the verticalrad[M⁰L⁰T⁰]

Valid when

  • r = l sinθ relates the circle's radius to the string length and angle

v(top, min) = √(gr)

Minimum speed at the top of a vertical circle

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At the critical (minimum) speed, gravity alone supplies the entire centripetal force — tension/normal force just touches zero

Valid when

  • Applies to a string/track providing tension/normal force only inward — below this speed, the object cannot maintain contact at the top and falls out of the circular path

Common mistakes

  • Below v(top,min), the object does NOT slow down and reverse — it leaves the circular path entirely and becomes a projectile

v(bottom, min) = √(5gr)

Minimum speed at the bottom to complete a full vertical circle

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Energy conservation from bottom to top (height gained = 2r) combined with v(top,min) = √(gr)

Valid when

  • This is THE single most tested numerical result in vertical circular motion — memorise both the value and its energy-conservation derivation

T = mv²/r − mg cosφ (φ measured from the TOP of the circle)

Tension at a general point on a vertical circle

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Newton's second law along the radial direction, with gravity's component toward/away from the centre depending on position

Variables used in this formula, with units and dimensions
SymbolMeaningUnitDimension
φangle of the current position measured from the top of the circlerad[M⁰L⁰T⁰]

Valid when

  • At the top (φ=0): T = mv²/r − mg; at the bottom (φ=180°): T = mv²/r + mg — sign of the gravity term flips

Common mistakes

  • The gravity term's sign depends on position — always re-derive it from a free-body diagram at that specific point rather than memorising one fixed sign

JEE Advanced frequently combines vertical-circle problems with energy conservation across multiple points, not just top/bottom — always set up energy conservation between the two points actually asked about, not just the standard top-bottom pair.

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